The Maximam Volume At STP Is Occupied By 1 12.8g Of So2 2 6.02 ...

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Most Upvoted Answer The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 m... Maximum Volume at STPAt STP (Standard Temperature and Pressure), the temperature is 273 K and the pressure is 1 atmosphere (atm). At this condition, one mole of any ideal gas occupies 22.4 L of volume. Therefore, the maximum volume at STP can be calculated for different substances.1. 12.8g of SO2To calculate the maximum volume occupied by 12.8g of SO2, we need to convert the mass to moles using the molar mass of SO2, which is 64 g/mol. moles of SO2 = 12.8 g / 64 g/mol = 0.2 molNow, using the ideal gas law, we can calculate the volume occupied by 0.2 mol of SO2 at STP.V = nRT/P = (0.2 mol)(0.0821 L atm/mol K)(273 K) / 1 atm = 4.4 L2. 6.02x10^23 molecules of CH4To calculate the maximum volume occupied by 6.02x10^23 molecules of CH4, we need to convert the number of molecules to moles using Avogadro's number.moles of CH4 = 6.02x10^23 / 6.022x10^23 mol^-1 = 1 molTherefore, the maximum volume occupied by 1 mol of CH4 at STP is 22.4 L.3. 0.5 mol of NO2To calculate the maximum volume occupied by 0.5 mol of NO2, we can use the ideal gas law.V = nRT/P = (0.5 mol)(0.0821 L atm/mol K)(273 K) / 1 atm = 11.2 L4. 1 gram molecule of CO2A gram molecule of CO2 is the amount of CO2 that has a mass of one mole. The molar mass of CO2 is 44 g/mol. Therefore, the mass of one gram molecule of CO2 is 44 g. To calculate the maximum volume occupied by one gram molecule of CO2 at STP, we can use the ideal gas law.moles of CO2 = 1 g / 44 g/mol = 0.023 molV = nRT/P = (0.023 mol)(0.0821 L atm/mol K)(273 K) / 1 atm = 0.5 LConclusionIn conclusion, the maximum volume occupied at STP depends on the amount and type of gas. The maximum volume is calculated using the ideal gas law, which relates the volume, pressure, temperature, and amount of gas. Therefore, the maximum volume occupied at STP by the substances given are:1. 12.8g of SO2 = 4.4 L2. 6.02x10^23 molecules of CH4 = 22.4 L3. 0.5 mol of NO2 = 11.2 L4. 1 gram molecule of CO2 = 0.5 L Answered by Sushil Kumar · View profile Community Answer The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 m... Download Answers PDF Share via Whatsapp Attention NEET Students!To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.

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View all The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ? Share with a Friend Answer this doubt Question Description The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ?. Solutions for The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Here you can find the meaning of The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ? defined & explained in the simplest way possible. Besides giving the explanation of The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ?, a detailed solution for The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ? has been provided alongside types of The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ? theory, EduRev gives you an ample number of questions to practice The maximam volume at sTP is occupied by 1 12.8g of so2 2 6.02x10'23 molecules of ch4 3 0.5 mol of No2 4 1grm molecule of co2 ? tests, examples and also practice NEET tests.

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