An Antifreeze Solution Is Prepared From 222.6 G Of Ethylene Glycol ...

SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Question1.55] An antifreeze solution is prepared from 222.6 g of ethylene glycol, C2H4(OH)2 and 200 g of water. Calculate the molality of the solution. If the density of the solution is 1.072 g mL-1, then what shall be the molarity of the solution? (Ans: i) 17.95 mol kg-1 ii) 9.11 mol L-1)Open in AppSolutionVerified by TopprWas this answer helpful?30Similar QuestionsQ1An antifreeze solution is prepared from $$222.6\,g$$ of ethylene glycol $$[C_2H_4(OH)_2]$$ and $$200\,g$$ of water. Calculate the molality of the solution. If the density of the solution is $$1.072\,g\,mL^{-1}$$ then what shall be the molarity of the solution ?View SolutionQ2

QUESTION 2.8

An antifreeze solution is prepared from 222.6 g of ethylene glycol (C2H6O2) and 200 g of water. Calculate the molality of the solution. If the density of the solution is 1.072gmL1, then what shall be the molarity of the solution?

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Q3

Anantifreeze solution is prepared from 222.6 g of ethylene glycol(C2H6O2)and 200 g of water. Calculate the molality of the solution. If thedensity of the solution is 1.072 g mL−1,then what shall be the molarity of the solution?

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Q4 Solve this: Q.7. An antifreeze solution is prepared from 222.6 g of ethylene glycol (C6H6O2) and 200 g of water (solvent). Calculate the molarity of the solution. 1) 0.414 2) 0.795 3) 4.14 4) 17.95View SolutionQ5The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113gcm3. Thus, the freezing point of the mixture is: (KfofH2O=1.86Kkgmol1)View Solution

Từ khóa » C2h6o2=c2h4