Answered: OH 1. Hg(OAc)2, H2O 2. NABH4 CH3 .CH3… | Bartleby

Skip to main contentHomework Help is Here – Start Your Trial Now!SEARCHHomework help starts here!ASK AN EXPERTASKScienceChemistryOH 1. Hg(OAc)2, H2O 2. NABH4 CH3 .CH3 H2C° H3C d-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H¯ adds to the sp² carbon with the most hydrogens to yield the most stab ocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. void the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with se phydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an anomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. w curved arrows to show the movement of electrons in this step of the mechanism. row-pushing Instructions AcO-Hg-OAc AcO-Hg OACOH 1. Hg(OAc)2, H2O 2. NABH4 CH3 .CH3 H2C° H3C d-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H¯ adds to the sp² carbon with the most hydrogens to yield the most stab ocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. void the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with se phydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an anomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. w curved arrows to show the movement of electrons in this step of the mechanism. row-pushing Instructions AcO-Hg-OAc AcO-Hg OACReportChemistryBUYChemistry 10th EditionISBN: 9781305957404Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher: Cengage Learning1 Chemical Foundations2 Atoms, Molecules, And Ions3 Stoichiometry4 Types Of Chemical Reactions And Solution Stoichiometry5 Gases6 Thermochemistry7 Atomic Structure And Periodicity8 Bonding: General Concepts9 Covalent Bonding: Orbitals10 Liquids And Solids11 Properties Of Solutions12 Chemical Kinetics13 Chemical Equilibrium14 Acids And Bases15 Acid-base Equilibria16 Solubility And Complex Ion Equilibria17 Spontaneity, Entropy, And Free Energy18 Electrochemistry19 The Nucleus: A Chemist's View20 The Representative Elements21 Transition Metals And Coordination Chemistry22 Organic And Biological MoleculesChapter QuestionsProblem 1RQProblem 2RQProblem 3RQProblem 4RQProblem 5RQProblem 6RQProblem 7RQProblem 8RQProblem 9RQProblem 10RQProblem 1ALQProblem 2ALQProblem 3ALQProblem 4ALQProblem 5ALQProblem 6ALQProblem 7ALQProblem 8ALQProblem 9ALQProblem 10ALQProblem 11ALQProblem 14ALQProblem 15ALQProblem 16ALQProblem 17ALQProblem 18ALQProblem 19QProblem 20QProblem 21QProblem 22QProblem 23QProblem 24QProblem 25QProblem 26QProblem 28QProblem 29QProblem 30QProblem 31EProblem 32EProblem 33EProblem 34EProblem 35EProblem 36EProblem 37EProblem 38EProblem 39EProblem 40EProblem 41EProblem 42EProblem 43EProblem 44EProblem 45EProblem 46EProblem 47EProblem 48EProblem 49EProblem 50EProblem 51EProblem 52EProblem 53EProblem 54EProblem 55EProblem 56EProblem 57EProblem 58EProblem 59EProblem 60EProblem 61EProblem 62EProblem 63EProblem 64EProblem 65EProblem 66EProblem 67EProblem 68EProblem 69EProblem 70EProblem 71EProblem 72EProblem 73EProblem 74EProblem 75EProblem 76EProblem 77EProblem 78EProblem 79EProblem 80EProblem 81EProblem 82EProblem 83EProblem 84EProblem 85EProblem 86EProblem 87EProblem 88EProblem 89EProblem 90EProblem 91EProblem 92EProblem 93AEProblem 94AEProblem 95AEProblem 96AEProblem 97AEProblem 98AEProblem 99AEProblem 100AEProblem 101AEProblem 102AEProblem 103AEProblem 104AEProblem 105AEProblem 106AEProblem 107AEProblem 108AEProblem 109AEProblem 110AEProblem 111CWPProblem 112CWPProblem 113CWPProblem 114CWPProblem 115CWPProblem 116CWPProblem 117CPProblem 118CPProblem 119CPProblem 120CPProblem 121CPProblem 122CPProblem 123CPProblem 124CPProblem 125CPSee similar textbooksBartleby Related Questions Icon

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OH 1. Hg(OAc)2, H20 2. NaBH4 .CH3 CH3 H2C H3C Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H* adds to the sp2 carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions AcO-Hg-OAc AcO-Hg OAc expand buttonTranscribed Image Text:OH 1. Hg(OAc)2, H20 2. NaBH4 .CH3 CH3 H2C H3C Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H* adds to the sp2 carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions AcO-Hg-OAc AcO-Hg OAc
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