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Answer\(x_{1}=1, x_{2}=-3\)ExplanationStep 1: Start with the given quadratic equation \(x^{2}+2x-3=0\). Step 2: Move the constant term to the other side to set the equation to zero, resulting in \(x^{2}+2x=3\). Step 3: To complete the square, add 1 to both sides to get \(x^{2}+2x+1=4\). Step 4: Recognize that the left side is now a perfect square trinomial, which can be written as \((x+1)^{2}=4\). Step 5: Take the square root of both sides to find \(x+1=\pm 2\). Step 6: Solve for \(x\) by subtracting 1 from both sides, resulting in \(x=1\) or \(x=-3\). Therefore, the solutions are \(x_{1}=1\) and \(x_{2}=-3\).Click to rate:93.1(338 votes)Search questionBy textBy image/screenshotDrop your file here orClick Hereto uploadTừ khóa » D=8 Cm H=8cm
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