F(x)=x 2 +xg'(1)+g''(2) And G(x)=f(1)x 2 +xf'(x)+f'(x) Then The Value Of F(3)
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Differential Calculus> f(x)=x 2 +xg’(1)+g’’(2) and g(x)=f(1)x 2 ...
f(x)=x2+xg’(1)+g’’(2)and g(x)=f(1)x2+xf’(x)+f’(x) then the value of f(3)
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