One Mole Of An Ideal Gas At NTP Occupies 22.4 Liters (molar Volume

QuestionOne mole of an ideal gas at NTP occupies 22.4 liters (molar volume). What is the ratio of molar volume to atomic volume to atomic volume of a mole of hydrogen ? Take size of hydrogen molecule to be 1 Å. Why is this ratio so large?

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Solution: Volume of one mole of ideal gas, Vg​ =22.4 litre =22.4×10−3m3 Radius of hydrogen molecule =1A/2 =0.5A=0.5×10−10m Volume of hydrogen molecule=4/3πr3 =4/3×22/7(0.5×10−10)3m3 =0.5238×10−30m3 One mole contains 6.023×1023 molecules. Volume of one mole of hydrogen, VH =0.5238×10−30×6.023×1023m3=3.1548×10−7m3 Now Vg​/VH​=22.4×10−3/3.1548×10−7=7.1×104 The ratio is very large. This is because the interatomic separation in the gas is very large compared to the size of a hydrogen molecule.Was this solution helpful?150ShareReportOne destination to cover all your homework and assignment needsLearn Practice Revision SucceedInstant 1:1 help, 24x760, 000+ Expert tutorsTextbook solutionsBig idea maths, McGraw-Hill Education etcEssay reviewGet expert feedback on your essaySchedule classesHigh dosage tutoring from Dedicated 3 expertsDownload AppExplore nowTrusted by 4 million+ students

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Question Text	One mole of an ideal gas at NTP occupies 22.4 liters (molar volume). What is the ratio of molar volume to atomic volume to atomic volume of a mole of hydrogen ? Take size of hydrogen molecule to be 1 Å. Why is this ratio so large?
Answer Type	Text solution:1
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