[Solved] 1 Kmol Of Any Gas At N.T.P Occupies Volume Of
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Download Solution PDF1 kmol of any gas at N.T.P occupies volume of This question was previously asked in ISRO IPRC Technical Assistant Mechanical 10 Dec 2016 Official Paper Download PDF Attempt Online View all ISRO Technical Assistant Papers >- 22.41 m3
- 2.241 m3
- 29.27 m3
- 1.03 m3
Answer (Detailed Solution Below)
Option 1 : 22.41 m3 Crack ISRO Technical Assistant with India's Super Teachers FREE Demo Classes Available* Explore Supercoaching For FREE
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Download Solution PDFConcept:
NTP
- The NTP is known as Normal temperature and pressure.
- The temperature at NTP is 20°C or 293.15 K
- The pressure at NTP is 1 atm or 101.35 kPa.
- The molar volume of an ideal gas at NTP is 22.4 L for one mole of a gas.
Molar volume at NTP is calculated by
\(V_m = \frac {RT}{P} = \frac {8.314\;×\;293.15}{101350}= 0.02241~m^3= 22.4~ L\)
where R = universal gas constant = 8.31 J K-1 mole-1, T = Temperature = 293.15 K, P = Pressure = 101.35 kPa = 101350 Pa
Calculation:
Given:
No of moles = 1 kmol = 1000 mol.
\(V_m = \frac {RT}{P} = \frac {8.314\;×\;293.15}{101350}= 0.02241~m^3\)
Volume of 1 kmol of ideal gas at NTP = 1000 × Vm = 1000 × 0.02241 m3 = 22.41 m3
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