Algebra InputsTrigonometry InputsCalculus InputsMatrix Inputs Basic algebra trigonometry calculus statistics matrices CharactersDifferentiate w.r.t. x x^{2}\left(3-8gxy\right)View solution stepsSteps Using Derivative Rule for Sum f ( x ) = x ^ { 3 } - 1 y g ( x ) 2 x ^ { 3 } - 1 To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4. \frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-1ygx^{4}\times 2-1) Multiply 1 and 2 to get 2. \frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-2ygx^{4}-1) The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}. 3x^{3-1}+4\left(-2gy\right)x^{4-1} Subtract 1 from 3. 3x^{2}+4\left(-2gy\right)x^{4-1} Multiply 4 times -2yg. 3x^{2}+\left(-8gy\right)x^{4-1} Subtract 1 from 4. 3x^{2}+\left(-8gy\right)x^{3} Evaluate x^{3}-2gyx^{4}-1QuizAlgebra f ( x ) = x ^ { 3 } - 1 y g ( x ) 2 x ^ { 3 } - 1
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14x^2y^3-6xy^2+16xyhttps://www.tiger-algebra.com/drill/14x~2y~3-6xy~2_16xy/ 14x2y3-6xy2+16xy Final result : 2xy • (7xy2 - 3y + 8) Step by step solution : Step 1 :Equation at the end of step 1 : (((14•(x2))•(y3))-(2•3xy2))+16xy Step 2 :Equation at the end of step 2 : ... 16x^4-24x^2y^3+9y^6https://www.tiger-algebra.com/drill/16x~4-24x~2y~3_9y~6/ 16x4-24x2y3+9y6 Final result : (4x2 - 3y3)2 Step by step solution : Step 1 :Equation at the end of step 1 : ((16•(x4))-((24•(x2))•(y3)))+32y6 Step 2 :Equation at the end of step 2 : ((16 • ... Find all critical points of f(x,y) = x^3 - 12xy + 8y^3 and state maximum, minimum, or saddle points.https://math.stackexchange.com/questions/473396/find-all-critical-points-of-fx-y-x3-12xy-8y3-and-state-maximum-mini Given: \tag 1 f(x,y) = x^3 - 12xy + 8y^3 Find and classify all critical points. The critical points are: (0,0) and (2,1). The partial derivatives are: f_x = 3x^2 -12 y f_y = -12x + 24y^2 ... 12x^3+36x^2+y+27xy^2https://www.tiger-algebra.com/drill/12x~3_36x~2_y_27xy~2/ 12x3+36x2+y+27xy2 Final result : 12x3 + 36x2 + 27xy2 + y Step by step solution : Step 1 :Equation at the end of step 1 : (((12•(x3))+(36•(x2)))+y)+33xy2 Step 2 :Equation at the end of step 2 ... 2x^3y+8x^2y^2-90xy^3https://www.tiger-algebra.com/drill/2x~3y_8x~2y~2-90xy~3/ 2x3y+8x2y2-90xy3 Final result : 2xy • (x + 9y) • (x - 5y) Step by step solution : Step 1 :Equation at the end of step 1 : (((2•(x3))•y)+((8•(x2))•(y2)))-(2•32•5xy3) Step 2 :Equation at the end ... How do you find the zeros of \displaystyle{y}={2}{x}^{{3}}-{8}{x}^{{2}}+{18}{x}-{72} ?https://socratic.org/questions/how-do-you-find-the-zeros-of-y-2x-3-8x-2-18x-72 Noah G Dec 30, 2016 This can be factored as \displaystyle{y}={2}{x}^{{2}}{\left({x}-{4}\right)}+{18}{\left({x}-{4}\right)}={\left({2}{x}^{{2}}+{18}\right)}{\left({x}-{4}\right)} ...More Items
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CopyCopied to clipboard\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-1ygx^{4}\times 2-1) To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-2ygx^{4}-1) Multiply 1 and 2 to get 2.3x^{3-1}+4\left(-2gy\right)x^{4-1} The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.3x^{2}+4\left(-2gy\right)x^{4-1} Subtract 1 from 3.3x^{2}+\left(-8gy\right)x^{4-1} Multiply 4 times -2yg.3x^{2}+\left(-8gy\right)x^{3} Subtract 1 from 4.
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Quadratic equation { x } ^ { 2 } - 4 x - 5 = 0Trigonometry 4 \sin \theta \cos \theta = 2 \sin \thetaLinear equation y = 3x + 4Arithmetic 699 * 533Matrix \left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]Simultaneous equation \left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.Differentiation \frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }Integration \int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d xLimits \lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}Back to top
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View solution stepsSteps Using Derivative Rule for Sum f ( x ) = x ^ { 3 } - 1 y g ( x ) 2 x ^ { 3 } - 1 To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4. \frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-1ygx^{4}\times 2-1) Multiply 1 and 2 to get 2. \frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-2ygx^{4}-1) The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}. 3x^{3-1}+4\left(-2gy\right)x^{4-1} Subtract 1 from 3. 3x^{2}+4\left(-2gy\right)x^{4-1} Multiply 4 times -2yg. 3x^{2}+\left(-8gy\right)x^{4-1} Subtract 1 from 4. 3x^{2}+\left(-8gy\right)x^{3} Evaluate x^{3}-2gyx^{4}-1
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